3[z-(1-2z)]+2=-10

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Solution for 3[z-(1-2z)]+2=-10 equation:


Simplifying
3[z + -1(1 + -2z)] + 2 = -10
3[z + (1 * -1 + -2z * -1)] + 2 = -10
3[z + (-1 + 2z)] + 2 = -10

Reorder the terms:
3[-1 + z + 2z] + 2 = -10

Combine like terms: z + 2z = 3z
3[-1 + 3z] + 2 = -10
[-1 * 3 + 3z * 3] + 2 = -10
[-3 + 9z] + 2 = -10

Reorder the terms:
-3 + 2 + 9z = -10

Combine like terms: -3 + 2 = -1
-1 + 9z = -10

Solving
-1 + 9z = -10

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 9z = -10 + 1

Combine like terms: -1 + 1 = 0
0 + 9z = -10 + 1
9z = -10 + 1

Combine like terms: -10 + 1 = -9
9z = -9

Divide each side by '9'.
z = -1

Simplifying
z = -1

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